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Permutation and Combination - Quant/Math - CAT 2013
Question 4 the day:
September 02, 2003
The question for the day is from the topic of Permutation and Combination.
- When four fair dice are rolled simultaneously, in how many outcomes will at least one of the dice show 3?
| (1) |
155 |
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(2) |
620 |
| (3) |
671 |
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(4) |
625 |
Correct Answer - (3)
Solution:
When 4 dice are rolled simultaneously, there will be a total of 64 = 1296 outcomes.
The number of outcomes in which none of the 4 dice show 3 will be 54 = 625 outcomes.
Therefore, the number of outcomes in which at least one die will show 3 = 1296 – 625 = 671
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