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Mensuration - Quant/Math - CAT 2013

  1. Algebra
  2. Progressions
  3. Averages
  4. Clocks and Calendars
  5. Data Sufficiency
  6. English Grammar
  7. Function
  8. Geometry
  9. Coordinate Geometry
  10. Interest
  11. Mensuration
  12. Mixtures & Alligations
  13. Number System
  14. Percentages
  15. Permutation & Combination
  16. Pipes & Cisterns And Work & Time
  17. Probability
  18. Profit & Loss
  19. Races
  20. Ratio, Proportion
  21. Speed, Time & Distance
  22. Trigonometry
  23. Miscellaneous
  24. General Knowledge
Question 4 the day: September 30, 2003

The question for the day is from the topic of Mensuration.
The circumference of the front wheel of a cart is 30 ft long and that of the back wheel is 36 ft long. What is the distance travelled by the cart, when the front wheel has done five more revolutions than the rear wheel?

(1) 20 ft (2) 25 ft
(3) 750 ft (4) 900 ft
Correct Answer - (4)

Solution:


The circumference of the front wheel is 30 ft and that of the rear wheel is 36 feet.

Let the rear wheel make n revolutions. At this time, the front wheel should have made n+5 revolutions.

As both the wheels would have covered the same distance, n*36 = (n+5)*30

36n = 30n + 150

6n = 150

n = 25.

Distance covered = 25*36 = 900 ft.




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