|
|
Geometry - Quant/Math - CAT 2009
Question 4 the day:
September 12, 2003
The question for the day is from the topic of Geometry.
- What is the measure of in radius of the triangle whose sides are 24, 7 and 25?
| (1) |
12.5 |
| |
(2) |
3 |
| (3) |
6 |
| |
(4) |
None of these |
Correct Answer - (2)
Solution:
We know that for any triangle, area of the triangle = r*s, where r is the in radius and s is the semi perimeter
As the given triangle is a right angled triangle, area of the triangle =  * 24 * 7 = 84 sq units.
S = semi perimeter = 
Therefore, 84 = 28 * r
=> r = 84/28 = 3
|
|
|
|
