|
|
Permutation and Combination - Quant/Math - CAT 2009
Question 4 the day:
October 08, 2003
The question for the day is from the topic of Permutation and Combination.
- How many words of 4 consonants and 3 vowels can be made from 12 consonants and 4 vowels, if all the letters are different?
| (1) |
16C7 * 7! |
| |
(2) |
12C4 * 4C3 * 7! |
| (3) |
12C3 * 4C4 |
| |
(4) |
12C4 * 4C3 |
Correct Answer - (2)
Solution:
4 consonants out of 12 can be selected in 12C4 ways.
3 vowels can be selected in 4C3 ways.
Therefore, total number of groups each containing 4 consonants and 3 vowels = 12C4 * 4C3
Each group contains 7 letters, which can be arranging in 7! ways.
Therefore required number of words = 124 * 4C3 * 7!
|
|
|
|
