Ascent Education Home
• CAT 2010 for IIMs
CAT - Intensive Contact Class @ Chennai
» CAT - Weekend Crash Course
» CAT - Correspondence
• India
• Abroad
» Mock CAT Series
» CAT - Math & DI Boot Camp
» Math Shortcut Workshops
• TANCET 2010 @ Chennai
• XAT 2010
• TANCET Y! Groups
• GRE-GMAT
• US B Schools
• Faculty List
• Question A Day

Permutation and Combination - Quant/Math - CAT 2010

  1. Algebra
  2. Progressions
  3. Averages
  4. Clocks and Calendars
  5. Data Sufficiency
  6. English Grammar
  7. Function
  8. Geometry
  9. Interest
  10. Mensuration
  11. Mixtures & Alligations
  12. Number System
  13. Percentages
  14. Permutation & Combination
  15. Pipes & Cisterns And Work & Time
  16. Probability
  17. Profit & Loss
  18. Races
  19. Ratio, Proportion
  20. Speed, Time & Distance
  21. Trigonometry
  22. Miscellaneous
  23. General Knowledge
Question 4 the day: May 20, 2003

The question for the day is from the topic of Permutation and Combination.
A team of 8 students goes on an excursion, in two cars, of which one can seat 5 and the other only 4. In how many ways can they travel?

(1) 9 (2) 26
(3) 126 (4) 3920
Correct Answer - (3)

Solution:


There are 8 students and the maximum capacity of the cars together is 9.

We may divide the 8 students as follows

Case I: 5 students in the first car and 3 in the second

Or Case II: 4 students in the first car and 4 in the second

Hence, in Case I: 8 students are divided into groups of 5 and 3 in 8C3 ways.

Similarly, in Case II: 8 students are divided into two groups of 4 and 4 in 8C4 ways.

Therefore, the total number of ways in which 8 students can travel is 8C3 + 8C4 = 56 + 70 = 126.




Page top        

 
  © 2002 - 10 ASCENT Education all rights reserved.