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Logarithm - Quant/Math - CAT 2009
Question 4 the day:
May 28, 2003
The question for the day is from the topic of Logarithm.
- If log 2 = 0. 3010, then find how many digits are contained in the number 256.
| (1) |
15 |
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(2) |
16 |
| (3) |
17 |
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(4) |
Cannot be determined |
Correct Answer - (3)
Solution:
Note: To find the number of digits contained in the number, increment the characteristic (integral part) of the logarithmic value of the number by one.
Taking log of the given number, we get log 256 = 56* log 2 = 56 * 0. 3010 = 16. 85.
Here the characteristic (integral part) = 16.
Therefore, number of digits contained in the number 256 is 16 + 1 = 17.
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