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Percentage - Quant/Math - CAT 2009
Question 4 the day:
March 17, 2003
The question for the day is from the topic Percentage
When processing flower-nectar into honeybees' extract, a considerable amount of water gets reduced. How much flower-nectar must be processed to yield 1kg of honey, if nectar contains 50% water, and the honey obtained from this nectar contains 15% water?
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| (1) |
1.5 kgs |
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(2) |
1.7 kgs |
| (3) |
3.33 kgs |
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(4) |
None of these |
Correct Answer - (2)
Solution:
Flower-nectar contains 50% of non-water part.
In honey this non-water part constitutes 85% (100-15).
Therefore 0.5 X Amount of flower-nectar = 0.85 X Amount of honey = 0.85 X 1 kg
Therefore amount of flower-nectar needed = (0.85/0.5) * 1kg = 1.7 kg.
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