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Pipes and Cisterns - Quant/Math - CAT 2009

  1. Algebra
  2. Progressions
  3. Averages
  4. Clocks and Calendars
  5. Data Sufficiency
  6. English Grammar
  7. Function
  8. Geometry
  9. Interest
  10. Mensuration
  11. Mixtures & Alligations
  12. Number System
  13. Percentages
  14. Permutation & Combination
  15. Pipes & Cisterns And Work & Time
  16. Probability
  17. Profit & Loss
  18. Races
  19. Ratio, Proportion
  20. Speed, Time & Distance
  21. Trigonometry
  22. Miscellaneous
  23. General Knowledge
Question 4 the day: July 29, 2002
The question for the day is a pipes and cisterns problem.
Pipe A usually fills a tank in 2 hours. On account of a leak at the bottom of the tank, it takes pipe A 30 more minutes to fill the tank. How long will the leak take to empty a full tank if pipe A is shut?
(1) 2 hours 30 minutes   (2) 5 hours   (3) 4 hours   (4) 10 hours
Correct Answer - (4)


Solution:

Pipe A fills the tank normally in 2 hours. Therefore, it will fill ½ of the tank in an hour.
Let the leak take x hours to empty a full tank when pipe A is shut. Therefore, the leak will empty of the tank in an hour.

The net amount of water that gets filled in the tank in an hour when pipe A is open and when there is a leak = of the tank. — (1)
When there is a leak, the problem states that Pipe A takes two and a half hours to fill the tank. i.e. hours. Therefore, in an hour, of the tank gets filled. – (2)
Equating (1) and (2), we get => => x = 10 hours.

The problem can also be mentally done as follows.

Pipe A takes 2 hours to fill the tank. Therefore, it fills half the tank in an hour or 50% of the tank in an hour.
When there is a leak it takes 2 hours 30 minutes for the tank to fill. i.e hours to fill the tank or or 40% of the tank gets filled.

On account of the leak, (50 - 40)% = 10% of the water gets wasted every hour. Therefore, the leak will take 10 hours to drain a full tank.

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