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Speed, Time and Distance. - Quant/Math - CAT 2009

  1. Algebra
  2. Progressions
  3. Averages
  4. Clocks and Calendars
  5. Data Sufficiency
  6. English Grammar
  7. Function
  8. Geometry
  9. Interest
  10. Mensuration
  11. Mixtures & Alligations
  12. Number System
  13. Percentages
  14. Permutation & Combination
  15. Pipes & Cisterns And Work & Time
  16. Probability
  17. Profit & Loss
  18. Races
  19. Ratio, Proportion
  20. Speed, Time & Distance
  21. Trigonometry
  22. Miscellaneous
  23. General Knowledge
Question 4 the day: February 23, 2004

The question for the day is based on some basic Speed, Time and Distance concepts.
Jim travels the first 3 hours of his journey at 60 mph speed and the remaining 5 hours at 24 mph speed. What is the average speed of Jim's travel in mph?

(1) 42 mph (2) 36 mph
(3) 37.5 mph (4) 42.5 mph
Correct Answer - (3)

Solution:

Average speed = .

Total distance traveled by Jim = Distance covered in the first 3 hours + Distance covered in the next 5 hours.

Distance covered in the first 3 hours = 3 * 60 = 180 miles
Distance covered in the next 5 hours = 5 * 24 = 120 miles

Therefore, total distance traveled = 180 + 120 = 300 miles.

Total time taken = 3 + 5 = 8 hours.

Average speed = = 37.5 mph.

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