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Mixtures and Alligation - Quant/Math - CAT 2009

  1. Algebra
  2. Progressions
  3. Averages
  4. Clocks and Calendars
  5. Data Sufficiency
  6. English Grammar
  7. Function
  8. Geometry
  9. Interest
  10. Mensuration
  11. Mixtures & Alligations
  12. Number System
  13. Percentages
  14. Permutation & Combination
  15. Pipes & Cisterns And Work & Time
  16. Probability
  17. Profit & Loss
  18. Races
  19. Ratio, Proportion
  20. Speed, Time & Distance
  21. Trigonometry
  22. Miscellaneous
  23. General Knowledge
Question 4 the day: August 06, 2003

The question for the day is from the topic of Mixtures and Alligation.
A zookeeper counted the heads of the animals in a zoo and found it to be 80. When he counted the legs of the animals he found it to be 260. If the zoo had either pigeons or horses, how many horses were there in the zoo?

(1) 40 (2) 30
(3) 50 (4) 60
Correct Answer - (3)

Solution:


Let the number of horses = x

Then the number of pigeons = 80 – x.

Each pigeon has 2 legs and each horse has 4 legs.

Therefore, total number of legs = 4x + 2(80-x) = 260

=>4x + 160 – 2x = 260

=>2x = 100

=>x = 50.




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