Ratio, Proportion - Quant/Math - CAT 2009
Question 4 the day:
August 28, 2002
The question for the day is from the topic of Ratio, Proportion.
- A predator is chasing its prey. The predator takes 4 leaps for every 6 leaps of the prey and the predator covers as much distance in 2 leaps as 3 leaps of the prey. Will the predator succeed in getting its food?
| (1) |
Yes |
| (2) |
In the 6th leap |
| (3) |
Never |
| (4) |
Cannot determine |
Correct Answer - (4)
Solution:
Distance covered in 2 leaps by predator = 3 leaps of the prey.
Distance covered in 1 leap of predator = 3/2 leaps of prey. ----(1)
4 leaps of predator : 6 leaps of prey ----(2)
Using (1) and (2), we get
4*3/2 leaps of predator : 6 leaps of prey.
=> 1:1
If the predator and prey start simultaneously at the same point, the predator will catch the prey immediately. If not so, then the predator will never catch the prey as it was running at the same speed.
As it was not mentioned in the question that they start simultaneously from the same point or not, we can't determine the answer. Therefore, the answer choice is (4).
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