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Percentages - Quant/Math - CAT 2013

  1. Algebra
  2. Progressions
  3. Averages
  4. Clocks and Calendars
  5. Data Sufficiency
  6. English Grammar
  7. Function
  8. Geometry
  9. Coordinate Geometry
  10. Interest
  11. Mensuration
  12. Mixtures & Alligations
  13. Number System
  14. Percentages
  15. Permutation & Combination
  16. Pipes & Cisterns And Work & Time
  17. Probability
  18. Profit & Loss
  19. Races
  20. Ratio, Proportion
  21. Speed, Time & Distance
  22. Trigonometry
  23. Miscellaneous
  24. General Knowledge
CAT Sample Questions - Question 4 the day : April 15, 2004

The question for the day is from the topic Percentages.

In an election contested by two parties, Party D secured 12% of the total votes more than Party R. If party R got 132,000 votes, by how many votes did it lose the election?

(1) 300,000   (2) 168,000
(3) 36,000   (4) 24,000

Correct choice - (3) Correct Answer -(36,000)

Explanatory Answer

Let the percentage of the total votes secured by Party D be x%
Then the percentage of total votes secured by Party R = (x – 12)%

As there are only two parties contesting in the election, the sum total of the votes secured by the two parties should total up to 100%

i.e., x + x – 12 = 100
2x – 12 = 100
or 2x = 112 or x = 56%.

If Party D got 56% of the votes, then Party got (56 – 12) = 44% of the total votes.

44% of the total votes = 132,000
i.e., = 132,000
ð     T = = 300,000 votes.

The margin by which Party R lost the election = 12% of the total votes
= 12% of 300,000 = 36,000.

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