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Percentages - Quant/Math - CAT 2009

  1. Algebra
  2. Progressions
  3. Averages
  4. Clocks and Calendars
  5. Data Sufficiency
  6. English Grammar
  7. Function
  8. Geometry
  9. Interest
  10. Mensuration
  11. Mixtures & Alligations
  12. Number System
  13. Percentages
  14. Permutation & Combination
  15. Pipes & Cisterns And Work & Time
  16. Probability
  17. Profit & Loss
  18. Races
  19. Ratio, Proportion
  20. Speed, Time & Distance
  21. Trigonometry
  22. Miscellaneous
  23. General Knowledge
CAT Sample Questions - Question 4 the day : April 15, 2004

The question for the day is from the topic Percentages.

In an election contested by two parties, Party D secured 12% of the total votes more than Party R. If party R got 132,000 votes, by how many votes did it lose the election?

(1) 300,000   (2) 168,000
(3) 36,000   (4) 24,000

Correct choice - (3) Correct Answer -(36,000)

Explanatory Answer

Let the percentage of the total votes secured by Party D be x%
Then the percentage of total votes secured by Party R = (x – 12)%

As there are only two parties contesting in the election, the sum total of the votes secured by the two parties should total up to 100%

i.e., x + x – 12 = 100
2x – 12 = 100
or 2x = 112 or x = 56%.

If Party D got 56% of the votes, then Party got (56 – 12) = 44% of the total votes.

44% of the total votes = 132,000
i.e., = 132,000
ð     T = = 300,000 votes.

The margin by which Party R lost the election = 12% of the total votes
= 12% of 300,000 = 36,000.

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